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Answer:
SOLUTION: Find the lcm of 6, 15 and 18 the lcm of 6, 15 and 18 =2\times3\times3\times5\ =90\ LCM + REMAINDER = 90+5=95 Hence, the required number is 95.
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To do: find the least number which when divided by615 and 18 leaves Remainder 5 in each case Solution: To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number. L.C.M. of 6, 5 and 18 6 = 2$\times$3 15 = 3$\times$5 18 = 2$\times$3$\times$3 L.C.M. of 6, 15 and 18 = 2$\times$3$\times$3$\times$5 = 90 Now, 5 $+$ 90 = 95 Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case. |