# 4. find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.

 Prev Question 5 Exercise 3.7 Next Answer: SOLUTION: Find the lcm of 6, 15 and 18 the lcm of 6, 15 and 18 =2\times3\times3\times5\ =90\ LCM + REMAINDER = 90+5=95 Hence, the required number is 95. Was This helpful? To do: find the least number which when divided by615 and 18 leaves Remainder 5 in each caseSolution:To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.L.C.M. of 6, 5 and 18  6 = 2$\times$315 = 3$\times$518 = 2$\times$3$\times$3L.C.M. of 6, 15 and 18 = 2$\times$3$\times$3$\times$5                                         = 90Now, 5 $+$ 90 = 95Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.